C Program to check whether a given number is Armstrong or Not

FIND IS GIVEN NUMBER ARMSTRONG OR NOT

Code :

#include<stdio.h>

int main()

{

    int num, sum=0, temp=0, res;

   

    printf("Enter a 3 digit number : ");

    scanf("%d", &num);

    temp = num;

   

    while(temp != 0)

    {

        res = temp % 10;

        sum += (res*res*res);

        temp = temp/10;

    }

   

   

    if(num == sum)

    {

        printf("\n\t%d is an Armstrong number",                               num);

    }

    else

    {

        printf("\n\t%d is Not  Armstrong number",                            num);

    }

    return 0;

}

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