C Program To Count Parity in Given sequence of numbers

 PARITY COUNTER

Code :

#include<stdio.h>

int main()
{
    int total_en = 0, even_en = 0, odd_en = 0, seq=0;

    printf("==================================\n");
    printf("\t  PARITY COUNTER\n");
    printf("==================================\n");

    printf("Enter sequence of numbers \n(Terminated by -1) : ");   
    while(seq != -1)
    {
        scanf("%d", &seq);
        if(seq == -1)
        {
           break;
        }
        if(seq%2 == 0)
        {
            even_en++;
        }
        else
        {
            odd_en++;
        }
        total_en++;
    }
   
    printf("\nTotal number of entries = %d\n", total_en);
    printf("No of Evens = %d\n", even_en);
    printf("No of Odds = %d\n", odd_en);
    printf("-----------------------------------\n");
    return 0;
}

Come again Learn again !

« iCodeBuzz »